Question

Golden Gate Bridge Completed in 1937, San Francisco’s Golden Gate Bridge is 2.7 km long and weighs about 890,000 tons. The length of the span between the two central towers is 1280 m; the towers themselves extend 152 m above the roadway. The cables that support the deck of the bridge between the two towers hang in a parabola (see figure). Assuming the origin is midway between the towers on the deck of the bridge, find an equation that describes the cables. How long is a guy wire that hangs vertically from the cables to the roadway 500 m from the center of the bridge?

Accepted Answer

Step 1: Define the coordinate system and variables. Place the origin at the midpoint between the two towers on the roadway, so the x-axis runs along the bridge deck and the y-axis measures the height of the cables above the roadway. The two towers are located at $$x = -640 m $$and $$x = 640 m ($$since the span between towers is 1280 m). The cable reaches its lowest point at the origin, so $$y(0) = 0. $$Step 2: Model the cable as a parabola. The general form of a parabola opening upwards with vertex at the origin is $$y = a x$$^{2}$$. We know the cable height at the towers is 152 m, so substitute x = 640$ and y = 152$ to find a$: 152 = a$$ $$(640)^{2}. $$Step 3: Solve for the coefficient $$a by $$rearranging the equation: $$a = \frac{152}{640$$^{2}$$}. $$This gives the specific equation of the parabola describing the cable: $$y = a x$$^{2}$$. Step 4: To find the length of the guy wire hanging vertically from the cable to the roadway at x = 500$ m, calculate the height of the cable at x = 500$ by substituting into the parabola equation: y(500) = a$$ $$(500)^{2}. $$Step 5: The length of the guy wire is simply the vertical distance from the cable to the roadway, which is $$y(500). $$This value represents how far the wire hangs down from the cable to the deck at 500 m from the center.

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Key Concepts

Parabolic Functions and Their Equations

Coordinate System and Symmetry

Evaluating the Parabola to Find Vertical Distances