Textbook Question
Graph each equation in Exercises 13 - 28. Let x = - 3, - 2, - 1, 0, 1, 2, 3
y = x3 - 1
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Ch. 1 - Equations and Inequalities
Blitzer8th EditionCollege AlgebraISBN: 9780136970514
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Table of contents
- Ch. P - Fundamental Concepts of Algebra311
- Ch. 1 - Equations and Inequalities398
- Ch. 2 - Functions and Graphs407
- Ch. 3 - Polynomial and Rational Functions306
- Ch. 4 - Exponential and Logarithmic Functions247
- Ch. 5 - Systems of Equations and Inequalities173
- Ch. 6 - Matrices and Determinants143
- Ch. 7 - Conic Sections124
- Ch. 8 - Sequences, Induction, and Probability251
Chapter 2, Problem 27
Solve each equation. Then state whether the equation is an identity, a conditional equation, or an inconsistent equation. (3x+1)/3 - 13/2 = (1-x)/4
Verified step by step guidance1
Start by writing down the given equation: \(\frac{3x+1}{3} - \frac{13}{2} = \frac{1 - x}{4}\).
To eliminate the fractions, find the least common denominator (LCD) of 3, 2, and 4, which is 12. Multiply every term on both sides of the equation by 12 to clear the denominators.
Distribute 12 to each term: \(12 \times \frac{3x+1}{3} - 12 \times \frac{13}{2} = 12 \times \frac{1 - x}{4}\).
Simplify each term after multiplication: \(4(3x+1) - 6(13) = 3(1 - x)\).
Now, expand the parentheses and solve the resulting linear equation for \(x\). After finding \(x\), check if the solution satisfies the original equation to determine if it is an identity, conditional, or inconsistent equation.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Solving Linear Equations
Solving linear equations involves isolating the variable on one side to find its value. This often requires clearing fractions by finding a common denominator or multiplying both sides by the least common multiple. Understanding how to manipulate equations step-by-step is essential to find the solution accurately.
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Types of Equations: Identity, Conditional, and Inconsistent
An identity is true for all values of the variable, a conditional equation is true for specific values, and an inconsistent equation has no solution. Recognizing these types helps interpret the solution set after solving the equation, indicating whether the equation holds universally, sometimes, or never.
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Working with Rational Expressions
Rational expressions are fractions with polynomials in the numerator and denominator. Solving equations involving them requires careful handling of denominators to avoid division by zero and to simplify expressions correctly. Clearing denominators by multiplying through is a common strategy to simplify the equation.
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Related Practice
Textbook Question
In Exercises 21–28, divide and express the result in standard form. (2 + 3i)/(2 + i)
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Textbook Question
The length of the rectangular tennis court at Wimbledon is 6 feet longer than twice the width. If the court's perimeter is 228 feet, what are the court's dimensions?
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Textbook Question
Graph each equation in Exercises 13 - 28. Let x = - 3, - 2, - 1, 0, 1, 2, 3
y = x3
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Textbook Question
Exercises 27–40 contain linear equations with constants in denominators. Solve each equation. x/3 = x/2 - 2
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Textbook Question
Solve each equation in Exercises 15–34 by the square root property.
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