Table of contents

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1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Naming Ionic Compounds

General Chemistry

3. Chemical Reactions

Naming Ionic Compounds

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Multiple Choice

Which of the following is the correct IUPAC formula for lead(IV) carbonate?

PbCO3

Pb2CO3

Pb2(CO3)4

Pb(CO3)2

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Verified step by step guidance

Identify the oxidation state of lead in lead(IV) carbonate. The Roman numeral IV indicates that lead has a +4 charge (Pb^{4+}).

Determine the charge of the carbonate ion. The carbonate ion (CO_3) has a charge of -2 (CO_3^{2-}).

Balance the total positive and negative charges to form a neutral compound. Since Pb is +4 and each CO_3 is -2, you need two carbonate ions to balance one Pb^{4+} ion.

Write the formula by placing the lead ion and the carbonate ions with the appropriate subscripts to reflect the ratio: one Pb ion and two CO_3 ions, which is Pb(CO_3)_2.

Confirm that the overall charge of the compound is zero by multiplying the charge of each ion by its subscript and adding them: (+4) + 2 × (-2) = 0, ensuring the formula is electrically neutral.