Table of contents

1. Matter and Measurements4h 31m
2. Atoms and the Periodic Table5h 23m
3. Ionic Compounds2h 18m
4. Molecular Compounds2h 18m
5. Classification & Balancing of Chemical Reactions3h 17m
6. Chemical Reactions & Quantities2h 27m
7. Energy, Rate and Equilibrium3h 46m
8. Gases, Liquids and Solids3h 25m
9. Solutions4h 10m
10. Acids and Bases3h 29m
11. Nuclear Chemistry56m
BONUS: Lab Techniques and Procedures1h 38m
BONUS: Mathematical Operations and Functions47m
12. Introduction to Organic Chemistry1h 34m
13. Alkenes, Alkynes, and Aromatic Compounds2h 12m
14. Compounds with Oxygen or Sulfur1h 6m
15. Aldehydes and Ketones1h 1m
16. Carboxylic Acids and Their Derivatives1h 11m
17. Amines39m
18. Amino Acids and Proteins1h 51m
19. Enzymes1h 37m
20. Carbohydrates1h 41m
21. The Generation of Biochemical Energy2h 8m
22. Carbohydrate Metabolism2h 22m
23. Lipids2h 26m
24. Lipid Metabolism1h 45m
25. Protein and Amino Acid Metabolism1h 37m
26. Nucleic Acids and Protein Synthesis2h 54m

15. Aldehydes and Ketones

Naming Aldehydes

GOB Chemistry

15. Aldehydes and Ketones

Naming Aldehydes

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Problem 26c

Textbook Question

Draw a structure for a compound that meets each of the following descriptions:
c. An alpha-bromoaldehyde, C₄H₇BrO

Verified step by step guidance

Step 1: Understand the problem. The compound is an alpha-bromoaldehyde with the molecular formula C₄H₇BrO. This means it contains an aldehyde functional group (-CHO) and a bromine atom attached to the carbon adjacent to the carbonyl carbon (the alpha position).

Step 2: Start by drawing the aldehyde functional group. The aldehyde group consists of a carbon atom double-bonded to an oxygen atom and single-bonded to a hydrogen atom. This carbon is part of the main chain.

Step 3: Add the alpha-bromo group. Identify the carbon adjacent to the aldehyde carbon (the alpha carbon) and attach a bromine atom to it.

Step 4: Complete the carbon chain to satisfy the molecular formula C₄H₇BrO. Ensure the total number of carbons in the structure is four, and adjust the remaining bonds with hydrogen atoms to satisfy the valency of each carbon atom.

Step 5: Verify the structure. Confirm that the structure contains exactly one aldehyde group, one bromine atom on the alpha carbon, and the molecular formula matches C₄H₇BrO. Ensure all atoms follow the octet rule where applicable.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Alpha-Bromoaldehyde

An alpha-bromoaldehyde is a type of aldehyde where a bromine atom is attached to the carbon atom adjacent to the carbonyl group (C=O). This positioning is crucial as it influences the compound's reactivity and properties. The 'alpha' designation indicates the location of the bromine relative to the functional group, which is essential for understanding its chemical behavior.

Molecular Formula Interpretation

The molecular formula C₄H₇BrO indicates that the compound contains four carbon atoms, seven hydrogen atoms, one bromine atom, and one oxygen atom. Understanding how to interpret this formula is vital for constructing the correct structure, as it provides insights into the connectivity and arrangement of atoms within the molecule, guiding the drawing of its structural representation.

Structural Representation of Organic Compounds

Structural representation involves depicting the arrangement of atoms in a molecule, including bonds and functional groups. For organic compounds like alpha-bromoaldehydes, it is important to accurately illustrate the carbon skeleton, functional groups, and any substituents. This visual representation aids in understanding the compound's chemical properties and potential reactions.

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Related Practice

Textbook Question

Which of the following molecules contain aldehyde or ketone functional groups? You may want to refer to Table 15.1, Table 12.1, and Figure 15.3 to help in your identification. Copy the formulas and circle these functional groups.

d. C₄H₉COCH₃

e. C₄H₉CHO

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