Use your answer from Problem 7.53 to calculate the following:[N2O...

Question

Use your answer from Problem 7.53 to calculate the following:[N2O4] at equilibrium when [NO2] = 0.0250 mol/L

Accepted Answer

Welcome back, everyone. We need to consider the equilibrium reaction and calculate the concentration of flooring gas at equilibrium. When our concentration of flooring equals 5.25 times 10 to the negative fourth power moles per liter. Our reaction given is di atomic flooring gas in equilibrium with two moles of flooring gas where our equilibrium constant K is equal to 7.40 times 10 to the negative 13th power at 500. Kelvin. Let's write out our equilibrium expression where we have our given K value equilibrium constant equal to 7.40 times 10 to the negative 13 power from the prompt. And recall that our equilibrium constant K is equal to our concentration of products raised to their geometric coefficients as exponents divided by our concentration of reactant raised to their psychometric coefficients as exponents. So this will be interpreted as 7.40 times 10 to the negative 13 power equal to in our numerator. Our concentration of our only gaseous product being flooring gas raised to its documentary coefficient of two. As an exponents in our denominator, we have our concentration of our only gaseous reactant being di atomic flooring F sub two with its metric coefficient of one which is implied. So we don't need to write it in as an exponents. So plugging in our given concentration of flooring in the numerator, we have our equilibrium constant K 7.40 times 10 to the negative 13 power equal to in our numerator. Our concentration of flooring is 5.25 times 10 to the negative fourth power moles per liter. This is squared and this is divided by our concentration of di atomic flooring gas. So to get our concentration of diatonic flooring gas, we're going to multiply both sides by our concentration of diatonic flooring so that it cancels out on the right. And now in our next line will have 7.40 times 10 to the negative 13th power times the concentration of flooring gas equal to 5.25 times 10 to the negative fourth power moles per liter as our concentration of flooring. So to isolate for our concentration of di atomic flooring, we want to divide both sides by our equilibrium constant 7.40 times 10 to the negative 13th power so that it will cancel it on the left. And what we'll find is that our concentration of di atomic flooring is equal to the value and sorry, just to make a correction, our numerator should still be squared as it was before. So we have 5.25 times 10 to the negative fourth power moles per liter squared divided by 7.40 times 10 to the negative 13th power. And this result of this quotient gives us our final answer of three 0.72 times 10 to the ninth power moles per leader as our concentration of di atomic flooring at equilibrium. And this would be our final answer highlighted in yellow corresponding to choice C in the multiple choice. So I hope that this made sense and let us know if you have any questions.

Use your answer from Problem 7.53 to calculate the following:[N2O4] at equilibrium when [NO2] = 0.0250 mol/L

Key Concepts

Chemical Equilibrium

Equilibrium Constant (K)

Stoichiometry

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