Draw a Newman projection, similar to Figure 3-25 down the C1—C...

Question

Draw a Newman projection, similar to Figure 3-25 down the C1—C6 bond in the equatorial conformation of methylcyclohexane. Show that the equatorial methyl group is also anti to C5. (Using your models will help.)
<IMAGE>

Accepted Answer

Hey everyone, let's solve this problem and says draw the Newman projection for the chair form of 613, dimethyl, cyclo hexane around the bond between carbon one and carbon six, keeping both methyl groups in equatorial positions. Show that these methods groups are anti or anti to carbon five. Alright, so let's review the six steps that johnny has told us how to draw a Newman projection. So step one is draw the bond line structure which we already have so kindly drawn out for us here two, we're going to highlight the bond of interest warm market. Then we're going to place the eye down the length of the bond. We will also add any implied hydrogen to the bond of interest. So remember on our bond line structure, we don't have all the hydrogen is drawn out. So we'll draw any implied hydrogen around our bond of interest. So we don't forget them. When we draw our projection, then we'll draw start our projection drawing by drawing front and back carbons, Each with three groups and lastly will determine the dye ahead real ankle. Okay, so let's go through these steps, draw bond line structure. Check highlight bond of interest. It said carbon one and carbon six. So that is this bond right here between them. Check place I down the length of the bond so we can place our eye right here in front of carbon one. So it's like you are standing in front of carbon one and carbon six is behind carbon number one. And since we have a chair, we are also going to draw, it's sort of like our I will be back here. Okay, so we're seeing all of this drawn out together. Okay, so we'll actually have two little circles for our Newman projection add hydrogen is to bond of interest. So we will add this. This carbon already has the group's drawn out so our carbon number six needs to hydrogen. Right, let's draw them correctly. So since this is a chair and this corner is pointing up one hydrogen will be up in the axle position and the other hydrogen will be down in the equatorial position. And since we're drawing both Newman projections, let's also add for carbon number four. So this corner is also going up so we'll have hydrogen and axial position and a hydrogen down an equatorial position. Okay, and we'll just write carbons two and five S CH two. Since we don't have to draw out each group individually. Okay, step four. Check so now draw front and back carbons with three groups each. So let's get to drawing. So I'm gonna start with our value are specified carbons carbon one and carbon six. So we'll draw a circle here and carbon one is going to be in the front right and carbon six will be in the back. Carbon one. Carbon six will be in the back. Now let's add our groups. So carbon one has a hydrogen going down in the actual position hydrogen down in the axle position, it has a methyl group going up in the equatorial position And it has the CH two that connects the rest of our ring going up also. Okay, and that will go to our next circle. I guess we could draw the front of that circle as well while we're here. So we have carbon three now in this front so similar we have hydrogen down in the actual position, Methyl group equatorial up And then behind we'll have carbon four. Okay, back there. So now let's do the back side of these carbons. What groups are on those? So as we drew out in our structure up here, We saw that the hydrogen are up in the axial position on carbon six and down in the equatorial position. And then we have our CH two going down in that equatorial position. So it will be coming down this way And similar connection to carbon three. Right? Because that corner is down here Carbon five. So now on carbon four we have an up axial hydrogen and a down equatorial hydrogen. Okay, so that is all of our groups are front. Carbons have three groups each are back. Carbons have three groups each as well. So now we're determining the di hydro angle. So the problem specifies show that the methyl groups are anti to carbon five. So this is carbon five in the back. Right, let's highlight this. So we have carbon five and we have our methyl groups here. So what does anti mean? Let's recall Auntie means that the two largest groups are opposite Or 180° from each other. So is this the case between our methyl group and our CH two group for each carbon? Yes, because we have this methyl group going up in the equatorial position. This Ch two group is going down in the equatorial position on the other side, so that is 100 degrees 180 degrees From between those two groups. And similarly, we have this method group going up equatorial this siege to down equatorial. So that is also 180° or anti between those groups. Okay, that's it for this problem. I hope this video is helpful. And thank you for watching.

Draw a Newman projection, similar to Figure 3-25 down the C1—C6 bond in the equatorial conformation of methylcyclohexane. Show that the equatorial methyl group is also anti to C5. (Using your models will help.)
<IMAGE>

Key Concepts

Newman Projections

Equatorial vs. Axial Positions

Anti Conformation

Watch next

Draw a Newman projection, similar to Figure 3-25 down the C1—C6 bond in the ­equatorial conformation of methylcyclohexane. Show that the equatorial methyl group is also anti to C5. (Using your models will help.)<IMAGE>

Key Concepts

Newman Projections

Equatorial vs. Axial Positions

Anti Conformation

Watch next

Draw a Newman projection, similar to Figure 3-25 down the C1—C6 bond in the equatorial conformation of methylcyclohexane. Show that the equatorial methyl group is also anti to C5. (Using your models will help.)
<IMAGE>