Textbook Question
At what pH does 80% of the acid exist in its acidic form?
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Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry
Bruice8th EditionOrganic ChemistryISBN: 9780135213711
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Table of contents
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 1)31
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 2)65
- Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry84
- Ch. 3 - An Introduction to Organic Compounds:Nomenclature, Physical Properties, and Structure183
- Ch. 4 - Isomers: The Arrangement of Atoms in Space121
- Ch. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and Kinetics83
- Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions175
- Ch. 7 - The Reactions of Alkynes • An Introduction to Multistep Synthesis119
- Ch. 8 - Delocalized Electrons: Their Effect on Stability, pKa, and the Products of a Reaction • Aromaticity and Electronic Effects: An Introduction to the Reactions of Benzene148
- Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides212
- Ch. 10 - Reactions of Alcohols, Ethers, Epoxides, Amines, and Sulfur-Containing Compounds131
- Ch. 11 - Organometallic Compounds60
- Ch. 12 - Radicals90
- Ch. 13 - Mass Spectrometry; Infrared Spectroscopy; UV/Vis Spectroscopy62
- Ch. 14 - NMR Spectroscopy95
- Ch. 15 - Reactions of Carboxylic Acids and Carboxylic Acid Derivatives123
- Ch. 16 - Reactions of Aldehydes and Ketones • More Reactions of Carboxylic Acid Derivatives141
- Ch. 17 - Reactions at the Alpha-Carbon101
- Ch. 18 - Reactions of Benzene and Substituted Benzenes144
- Ch. 19 - More About Amines • Reactions of Heterocyclic Compounds49
- Ch. 20 - The Organic Chemistry of Carbohydrates80
- Ch. 21 - Amino Acids, Peptides, and Proteins57
- Ch. 22 - Catalysis in Organic Reactions and in Enzymatic Reactions35
- Ch. 23 - The Organic Chemistry of the Coenzymes—Compounds Derived from Vitamins1
- Ch. 28 - Pericyclic Reactions58
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Bruice 8th EditionCh. 2 - Acids and Bases: Central to Understanding Organic ChemistryProblem 74a
Bruice 8th EditionCh. 2 - Acids and Bases: Central to Understanding Organic ChemistryProblem 74aChapter 3, Problem 74a
How could you separate a mixture of the following compounds? The reagents available to you are water, ether, 1.0 M HCl, and 1.0 M NaOH.
Verified step by step guidance1
Step 1: Analyze the chemical properties of each compound in the mixture. The compounds include: (1) a carboxylic acid (pKa = 4.8), (2) a protonated amine (pKa = 4.85), (3) a phenol (pKa = 8.6), (4) an alkyl chloride (neutral), and (5) an ammonium salt (pKa = 10.7). These pKa values indicate their relative acidity or basicity, which will guide the separation process.
Step 2: Use 1.0 M NaOH to selectively deprotonate the carboxylic acid (pKa = 4.8) and phenol (pKa = 8.6). The carboxylic acid will form a carboxylate anion, which is water-soluble, while the phenol will also form a phenoxide anion, which is water-soluble. The other compounds will remain in the ether layer.
Step 3: Extract the aqueous layer containing the carboxylate and phenoxide ions. To separate these two compounds, acidify the aqueous layer with 1.0 M HCl. The carboxylate anion will revert to the carboxylic acid, which is insoluble in water and can be extracted into ether. The phenoxide ion will revert to phenol, which can also be extracted into ether.
Step 4: Use 1.0 M HCl to protonate the ammonium salt (pKa = 10.7) and the protonated amine (pKa = 4.85). The ammonium salt is already water-soluble, but the protonated amine will also become water-soluble. These compounds can be extracted into the aqueous layer, leaving the neutral alkyl chloride in the ether layer.
Step 5: Separate the aqueous layer containing the ammonium salt and protonated amine. To isolate the protonated amine, neutralize the aqueous layer with 1.0 M NaOH. The amine will revert to its neutral form and can be extracted into ether. The ammonium salt remains in the aqueous layer.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Acid-Base Properties
Understanding the acid-base properties of compounds is crucial for separation techniques. The pKa values indicate the strength of acids and bases; lower pKa values correspond to stronger acids. This knowledge helps predict how compounds will behave in acidic or basic environments, guiding the choice of reagents for effective separation.
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Solubility and Extraction
Solubility plays a key role in separating compounds using solvents like water and ether. Compounds with different polarities will preferentially dissolve in different solvents, allowing for their separation. For instance, organic compounds may dissolve in ether while ionic compounds may be more soluble in water, facilitating extraction based on solubility differences.
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Reagent Selection
The choice of reagents, such as 1.0 M HCl and 1.0 M NaOH, is essential for manipulating the ionization states of compounds. Acidic or basic conditions can convert neutral compounds into their ionic forms, enhancing their solubility in water. This principle is vital for separating compounds based on their acid-base characteristics and solubility in different solvents.
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Related Practice
Textbook Question
Given that pH + pOH = 14 and that the concentration of water in a solution of water is 55.5 M, show that the pKa of water is 15.7. (Hint: pOH=−log [HO−])
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Textbook Question
Citrus fruits are rich in citric acid, a compound with three COOH groups. Explain the following:
a. The first pKa (for the COOH group in the center of the molecule) is lower than the pKa of acetic acid.
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Textbook Question
If an acid with a pKa of 5.3 is in an aqueous solution of pH 5.7, what percentage of the acid is present in its acidic form?
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Textbook Question
Citrus fruits are rich in citric acid, a compound with three COOH groups. Explain the following:
b. The third pKa is greater than the pKa of acetic acid.
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