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Ch. 6 - Applications of Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 6, Problem 6.1.28b

Probe speed A data collection probe is dropped from a stationary balloon, and it falls with a velocity (in m/s) given by v(t) = 9.8t, neglecting air resistance. After 10 s, a chute deploys and the probe immediately slows to a constant speed of 10 m/s, which it maintains until it enters the ocean.


b. How far does the probe fall in the first 30 s after it is released?

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1
Identify the velocity function for the probe in two time intervals: from 0 to 10 seconds, the velocity is given by \(v(t) = 9.8t\), and from 10 to 30 seconds, the velocity is constant at \(v(t) = 10\) m/s.
To find the distance fallen in the first 10 seconds, integrate the velocity function \(v(t) = 9.8t\) with respect to time over the interval \([0, 10]\). This gives the displacement during free fall before the chute deploys: \(\int_0^{10} 9.8t \, dt\).
To find the distance fallen from 10 to 30 seconds, use the constant velocity \(v(t) = 10\) m/s. Since velocity is constant, the distance is velocity multiplied by time: \(10 \times (30 - 10)\).
Add the two distances obtained from the two intervals to get the total distance fallen in the first 30 seconds: \(\text{distance}_1 + \text{distance}_2\).
Express the total distance as the sum of the integral result and the constant velocity distance, which represents the full distance the probe falls in the first 30 seconds after release.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Velocity and Displacement Relationship

Velocity is the rate of change of displacement with respect to time. To find the distance fallen, you integrate the velocity function over the given time interval. This process accumulates the total displacement from the velocity data.
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Derivatives Applied To Velocity

Piecewise Functions in Motion

When an object’s velocity changes behavior at a certain time, its motion is described by a piecewise function. Here, velocity changes at 10 seconds, requiring separate integration for each time segment to find total displacement.
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Definite Integration for Distance Calculation

Definite integration of velocity over a time interval gives the exact displacement during that period. For constant velocity, displacement is velocity multiplied by time; for variable velocity, integration is necessary.
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Related Practice
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b. What is the SAV ratio of a ball with radius a? 

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