Textbook Question
Show how you might use SN2 reactions to convert 1-chlorobutane into the following compounds.
c. 1-iodobutane
d. CH3—(CH2)3—CN
2004
views
Ch.6 - Alkyl Halides; Nucleophilic Substitution
Wade9th EditionOrganic ChemistryISBN: 9780135213728
Not the one you use?Change textbookSelect a different textbook
Table of contents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
Chapter 6, Problem 16c,d
For each pair, predict the stronger nucleophile in the SN2 reaction (using an alcohol as the solvent). Explain your prediction.
c. NH3 or PH3
d. CH3S– or H2S
Verified step by step guidance1
Understand the concept of nucleophilicity: Nucleophilicity refers to the ability of a species to donate a pair of electrons to an electrophile. In SN2 reactions, stronger nucleophiles react faster. Factors affecting nucleophilicity include charge, electronegativity, solvent effects, and the size of the nucleophile.
Analyze the solvent: The problem specifies that the solvent is an alcohol, which is a polar protic solvent. Polar protic solvents can hydrogen bond with nucleophiles, stabilizing them and reducing their nucleophilicity. Larger, less electronegative atoms are less affected by this stabilization, making them stronger nucleophiles in polar protic solvents.
Compare NH3 and PH3: Nitrogen (N) is smaller and more electronegative than phosphorus (P). In a polar protic solvent, NH3 will be more stabilized by hydrogen bonding than PH3. Since PH3 is less stabilized, it will be the stronger nucleophile in this solvent.
Compare CH3S⁻ and H2S: CH3S⁻ is negatively charged, while H2S is neutral. Negatively charged species are generally stronger nucleophiles than their neutral counterparts. Additionally, sulfur (S) is larger and less electronegative than oxygen, so CH3S⁻ will be less stabilized by the polar protic solvent compared to H2S, making CH3S⁻ the stronger nucleophile.
Summarize the predictions: For part (c), PH3 is the stronger nucleophile in an alcohol solvent. For part (d), CH3S⁻ is the stronger nucleophile due to its negative charge and reduced stabilization in the polar protic solvent.
Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
5mWas this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Nucleophilicity
Nucleophilicity refers to the ability of a species to donate an electron pair to an electrophile during a chemical reaction. In SN2 reactions, stronger nucleophiles are typically negatively charged or have lone pairs that can readily participate in bond formation. Factors influencing nucleophilicity include charge, electronegativity, and solvent effects, with polar protic solvents often stabilizing nucleophiles and reducing their reactivity.
Recommended video:
Guided course
08:27
Nucleophilic Addition
SN2 Mechanism
The SN2 (substitution nucleophilic bimolecular) mechanism involves a single concerted step where the nucleophile attacks the electrophile, leading to the displacement of a leaving group. This reaction is characterized by a backside attack, resulting in inversion of configuration at the carbon center. The rate of the reaction depends on the concentration of both the nucleophile and the substrate, making it bimolecular.
Recommended video:
Guided course
08:33Drawing the SN2 Mechanism
Solvent Effects
The choice of solvent can significantly influence the nucleophilicity of reactants in an SN2 reaction. In polar protic solvents, such as alcohols, nucleophiles can be stabilized through hydrogen bonding, which can hinder their reactivity. Conversely, polar aprotic solvents do not solvate anions as effectively, often leading to increased nucleophilicity. Understanding how solvents interact with nucleophiles is crucial for predicting reaction outcomes.
Recommended video:
Guided course
01:16Identification of polarity in solvents
Related Practice
Textbook Question
For each pair, predict the stronger nucleophile in the SN2 reaction (using an alcohol as the solvent). Explain your prediction.
a. (CH3CH2)3N or (CH3CH2)2NH
b. (CH3)2O or (CH3)2S
677
views
Textbook Question
For each pair, predict the stronger nucleophile in the SN2 reaction (using an alcohol as the solvent). Explain your prediction.
e. (CH3)3N or (CH3)2O
f. CH3COO– or CF3COO–
1343
views
Textbook Question
For each pair, predict the stronger nucleophile in the SN2 reaction (using an alcohol as the solvent). Explain your prediction.
g. (CH3)2CHO– or CH3CH2CH2O–
h. I– or Cl–
831
views
Textbook Question
Show how you might use SN2 reactions to convert 1-chlorobutane into the following compounds.
e. CH3—(CH2)3—C≡CH
f. CH3CH2—O—(CH2)3—CH3
g. CH3—(CH2)3—NH2
1766
views
Textbook Question
When diethyl ether (CH3CH2OCH2CH3) is treated with concentrated HBr, the initial products are CH3CH2Br and CH3CH2OH. Propose a mechanism to account for this reaction.
2811
views