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Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Not the one you use?Change textbook
Chapter 22, Problem 69h

Predict the products of the following reactions.
(h) Chemical structure of acetoacetic ester synthesis with reaction conditions and reagents listed on the right.

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1
Step 1: Analyze the structure of the starting compound. The molecule contains two carbonyl groups: one in a ketone functional group and the other in an ester functional group. The reaction involves three steps: (1) treatment with sodium methoxide (NaOCH₃), (2) methyl iodide (CH₃I), and (3) acidic hydrolysis with heat (H₃O⁺, heat).
Step 2: In the first step, NaOCH₃ acts as a base and deprotonates the alpha-hydrogen (hydrogen adjacent to the ketone carbonyl group). This generates an enolate ion, which is a nucleophilic species capable of attacking electrophiles.
Step 3: In the second step, the enolate ion reacts with CH₃I, an alkylating agent. The enolate attacks the methyl group of CH₃I, resulting in the formation of a new C-C bond. This step introduces a methyl group at the alpha position of the ketone.
Step 4: In the third step, the molecule undergoes acidic hydrolysis (H₃O⁺, heat). The ester group is hydrolyzed to form a carboxylic acid. Additionally, decarboxylation may occur if the molecule contains a beta-keto acid structure after hydrolysis, leading to the loss of CO₂.
Step 5: The final product is a methylated ketone (due to the alkylation step) and potentially a simpler ketone structure if decarboxylation occurs. Carefully examine the reaction conditions and intermediates to predict the exact structure of the product.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

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