Textbook Question
Use bond-dissociation enthalpies (Table 4-2, p. 167) to calculate values of ΔH° for the following reactions.
a. CH3—CH3 + I2 → CH3CH2I + HI
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Ch.4 - The Study of Chemical Reactions
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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Table of contents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
Chapter 4, Problem 40c,d
Label each hydrogen atom in the following compounds as primary (1°), secondary (2°), or tertiary (3°).
(c) (CH3)2CHCH(CH3)CH2CH3
(d) 
Verified step by step guidance1
Step 1: Understand the definitions of primary, secondary, and tertiary hydrogen atoms. A primary hydrogen is attached to a primary carbon (a carbon bonded to only one other carbon). A secondary hydrogen is attached to a secondary carbon (a carbon bonded to two other carbons). A tertiary hydrogen is attached to a tertiary carbon (a carbon bonded to three other carbons).
Step 2: Analyze the structure of the compound (CH3)2CHCH(CH3)CH2CH3. Break down the structure to identify each carbon atom and its connectivity. The structure can be visualized as: CH3-CH(CH3)-CH(CH3)-CH2-CH3.
Step 3: Label the hydrogen atoms on each carbon. Start with the first carbon (CH3 group), which is a primary carbon, so all hydrogens here are primary hydrogens.
Step 4: Move to the second carbon (CH), which is bonded to three other carbons, making it a tertiary carbon. Therefore, the hydrogen attached to this carbon is a tertiary hydrogen.
Step 5: Continue to the third carbon (CH), which is bonded to two other carbons, making it a secondary carbon. Thus, the hydrogen attached to this carbon is a secondary hydrogen. Finally, the fourth carbon (CH2) is bonded to two other carbons, making it a secondary carbon, so the hydrogens here are secondary hydrogens.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Hydrogen Atom Classification
In organic chemistry, hydrogen atoms are classified based on the type of carbon atom they are attached to. A primary (1°) hydrogen is attached to a carbon bonded to only one other carbon, a secondary (2°) hydrogen is attached to a carbon bonded to two other carbons, and a tertiary (3°) hydrogen is attached to a carbon bonded to three other carbons. This classification helps in understanding the reactivity and properties of different hydrogen atoms in a molecule.
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Carbon Atom Classification
Carbon atoms in organic molecules are classified as primary, secondary, tertiary, or quaternary based on the number of other carbon atoms they are directly bonded to. A primary carbon is bonded to one other carbon, a secondary to two, a tertiary to three, and a quaternary to four. This classification is crucial for determining the structure and reactivity of organic compounds, especially in reactions like substitution and elimination.
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Structural Formula Interpretation
Understanding structural formulas is essential for identifying the connectivity and arrangement of atoms within a molecule. In the given compound (CH3)2CHCH(CH3)CH2CH3, each group represents a specific arrangement of carbon and hydrogen atoms. Interpreting these groups allows for the identification of primary, secondary, and tertiary hydrogens by analyzing the carbon framework and its connectivity, which is fundamental for solving the problem.
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Related Practice
Textbook Question
a. Draw an approximate reaction-energy diagram for the acid–base reaction of phenol (see below) with 1-molar aqueous sodium hydroxide solution.
b. On the same diagram, draw an approximate reaction-energy diagram for the acid–base reaction of tert-butyl alcohol (see below) with 1-molar aqueous sodium hydroxide solution.
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Textbook Question
Label each hydrogen atom in the following compounds as primary (1°), secondary (2°), or tertiary (3°).
(e)
(f)
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Textbook Question
Label each hydrogen atom in the following compounds as primary (1°), secondary (2°), or tertiary (3°).
(a) CH3CH2CH(CH3)2
(b) (CH3)3CCH2CH3
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Textbook Question
Treatment of tert-butyl alcohol with concentrated HCl gives tert-butyl chloride.
When the concentration of H+ is doubled, the reaction rate doubles. When the concentration of tert-butyl alcohol is tripled, the reaction rate triples. When the chloride ion concentration is quadrupled, however, the reaction rate is unchanged. Write the rate equation for this reaction.
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Textbook Question
Use bond-dissociation enthalpies (Table 4-2, p. 167) to calculate values of ΔH° for the following reactions.
b. CH3CH2Cl + HI → CH3CH2I + HCl
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