117. Suppose that the second derivative of the function y = f(x) isy" =(x+1)(x-2). For what x-values does the graph of f have an inflection point?
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To find the x-values where the graph of f has an inflection point, we need to determine where the second derivative changes sign. An inflection point occurs where the concavity of the function changes.
Start by setting the second derivative equal to zero: . Solve this equation to find the critical points.
Factor the equation: . This gives us two solutions: and .
To confirm these are inflection points, check the sign of the second derivative around these values. Choose test points in the intervals , , and .
Evaluate the sign of at these test points to determine if the sign changes. If the sign changes, then the corresponding x-value is an inflection point.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Second Derivative Test
The second derivative test is used to determine the concavity of a function and identify inflection points. An inflection point occurs where the second derivative changes sign, indicating a transition from concave up to concave down or vice versa. For the function y = f(x), the inflection points are found by setting the second derivative equal to zero and solving for x.
Factoring quadratic expressions involves rewriting them as a product of linear factors. In the given second derivative y'' = (x+1)(x-2), the expression is already factored, indicating potential x-values where the derivative equals zero. These values, x = -1 and x = 2, are critical for determining where the graph might have inflection points.
Sign change analysis involves examining the intervals around the roots of the second derivative to determine where the sign changes. This helps confirm the presence of inflection points. For y'' = (x+1)(x-2), check the sign of y'' in intervals around x = -1 and x = 2 to ensure it changes, confirming these x-values as inflection points.