Draw the condensed and skeletal structures for each of the fol...

Question

Draw the condensed and skeletal structures for each of the following:

c. isopropylacetylene

Accepted Answer

Welcome back everyone. And in States video, we are going to draw the skeletal and condense structures that corresponds the name given below ice albedo is settling. Now, before we begin this problem, let's look at the parent of this structure as settling. This is the simplest alkaline which corresponds to two carbon atoms bonded by a triple bond. Meaning since each carbon atom must have four bonds, there must be two hygiene atoms bonded to each carbon. This is a settling. But the main difference is that the structure that we're analyzing is is a bureau settling. So we're going to leave a settling as it does, but we're going to replace one of the hydrogen atoms with eyes of beetle. So we only want to understand how isa beetle submission looks like. You already know that normal beetle group or a straight chain beetle group has or carbon atoms in the straight chain. And the longest chain to get an isa beetle group, we are going to branch it and shorten our parents, we're going to draw a three member chain and then we are going to add the fourth carbon atom on the second one. Okay. So Now, if we fill the remaining hydrogen atoms, we will have three hydrants monitor death carbon because it must have four bonds, one at the 2nd 13 and the third one and this carbon bonded to the second one will be bonded to our parents. So that means we have two bonds, there must be two hydrogen atoms bonded said that's isa beetle. So if we see what we were trying to do, we are just going to get CH, then we are going to draw CC triple bond and replace that hydrogen with isil Beatles. So we have C S two which has done bonded to CH and that ch has two muscle groups, CH three CH three. Now this is not a condensed structure, this is not a skeletal structure. We just wanted to see how the structure looks like and we are ready to begin drawing the condensed structure. So let's suppose that we begin by drawing it from top to bottom. So if you look at it, we will essentially go from here. Let's suppose that this is carbon number one. Let's just omit these two metal groups, you will soon understand why. But let's suppose that we start with carbon number one with N C H going down, we have 234. So we're going to say that first of all, there are two metal groups. So let's add parentheses and state CH three inferences then add a subscript of two. So we're indicating that there are two C three groups bonded to the carbon atom that goes next. So we have to add ch now to clearly indicate that these two metal groups are bonded to our ch. Now ch is bonded to CS two. So we're going to add CH two, we are not showing any bonds, CS two is wanted to see. And now we are adding our triple bond, we are only showing that bond for the main functional group. In this case, our class of compound is alkaline. So we have to clearly show that triple bond, we're going to add our next carbon and then we have hydrogen. So this is our condensed structure. And now we are ready to draw the skeletal one to draw the skeletal structure. The best idea is to actually enumerate your longest chain. It doesn't really matter which direction you go. You just want to enumerate that. So you have an idea of how many carbon atoms you have. So let's suppose if we go from bottom to top, that would be 12345 carbon atoms. And you want to draw a chain that it has five carbon atoms. So that's our carbon number one. However, we have to create a 180° angle because we have a triple bond. So these carbon atoms are sp hybridized, we're going to create a triple bond. So that corresponds to the first carbon atom. Then we have the second one and we are going to create a bond between the second and the third one. It's still linear because we have sp hybridized carbon atom bonded to D H S and one then from carbon 3 to 4, we have an additional one and one more. So that's two total, right? If we have 123, 45. So notice how this has five carbon atoms in the longest chain, 12345. And now the fourth carbon atom has a metal group, 1234, this carbon atom has a metal group. So we're going to add a basic line because the vertex corresponds to one carbon atom. So there must be three implicit hydrogen is here to make sure that we have four bonds bonded to that carbon, right? So this is our final structure note that we don't need to calculate the number of hydrogen is because as long as you add your double and triple bonds and your substitutions, you automatically take care of all of the hydrogen atoms. Let's say if you look at the triple bond, you have ch because you see three bonds. So there must be one hydrogen here you have see only because you have four bonds, then you have ceased to because you have to bond. So there must be too high jeans here. You have ch because you have three bonds. So that makes sense. One hygiene is needed. And at every end, we have metal groups because we only see one verdicts. So there must be three hydrogen atoms bonded to each carbon to have a total of four bonds. We can label this is our final answer. And based on our answers, we can conclude that the correct answer to the multiple choice question is a Thank you for watching.

Draw the condensed and skeletal structures for each of the following:
c. isopropylacetylene

Key Concepts

Condensed Structures

Skeletal Structures

Isopropylacetylene

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