Textbook Question
Explain why each compound or ion should be aromatic, antiaromatic, or nonaromatic.
(d)
(e)
(f) the [20]annulene dication
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Ch. 16 - Aromatic Compounds
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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Table of contents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
Chapter 16, Problem 14
When 3-chlorocyclopropene is treated with AgBF4, AgCl precipitates. The organic product can be obtained as a crystalline material, soluble in polar solvents such as nitromethane but insoluble in hexane. When the crystalline material is dissolved in nitromethane containing KCl, the original 3-chlorocyclopropene is regenerated. Determine the structure of the crystalline material, and write equations for its formation and its reaction with chloride ion.
Verified step by step guidance1
Step 1: Analyze the reaction of 3-chlorocyclopropene with AgBF4. The Ag+ ion reacts with the Cl- ion from 3-chlorocyclopropene to form AgCl as a precipitate. This indicates that the Cl- ion is removed from the cyclopropene ring, leaving behind a positively charged cyclopropene cation.
Step 2: Consider the structure of the organic product. The removal of Cl- from 3-chlorocyclopropene results in the formation of a cyclopropene cation. This cation is stabilized by resonance and can interact with BF4- to form a crystalline salt, [cyclopropene]+[BF4]-.
Step 3: Write the equation for the formation of the crystalline material. The reaction can be represented as:
Step 4: Analyze the reaction of the crystalline material with KCl in nitromethane. The cyclopropene cation reacts with Cl- from KCl to regenerate 3-chlorocyclopropene. This demonstrates the reversible nature of the reaction.
Step 5: Write the equation for the regeneration of 3-chlorocyclopropene. The reaction can be represented as:
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Electrophilic Aromatic Substitution
Electrophilic aromatic substitution is a fundamental reaction in organic chemistry where an electrophile replaces a hydrogen atom on an aromatic ring. In the context of 3-chlorocyclopropene, the presence of the chlorine atom makes the compound more reactive towards electrophiles, facilitating the formation of a new product when treated with AgBF4. Understanding this mechanism is crucial for predicting the structure of the resulting crystalline material.
Solubility Principles
Solubility principles dictate that 'like dissolves like,' meaning polar substances tend to dissolve in polar solvents, while nonpolar substances dissolve in nonpolar solvents. The crystalline material's solubility in nitromethane (a polar solvent) but not in hexane (a nonpolar solvent) suggests that it possesses polar functional groups or characteristics, which is essential for determining its structure and behavior in reactions.
Nucleophilic Substitution Reactions
Nucleophilic substitution reactions involve the replacement of a leaving group (like Cl) by a nucleophile (such as KCl in this case). The regeneration of 3-chlorocyclopropene from the crystalline material upon treatment with KCl indicates that the crystalline product likely contains a reactive site that can undergo nucleophilic attack, leading to the reformation of the original compound. This concept is vital for writing the reaction equations and understanding the transformation processes involved.
Related Practice
Textbook Question
The following hydrocarbon has an unusually large dipole moment. Explain how a large dipole moment might arise.
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Textbook Question
a. Explain how pyrrole is isoelectronic with the cyclopentadienyl anion.
b. Specifically, what is the difference between the cyclopentadienyl anion and pyrrole?
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Textbook Question
The polarization of a carbonyl group can be represented by a pair of resonance structures:
Cyclopropenone and cycloheptatrienone are more stable than anticipated. Cyclopentadienone, however, is relatively unstable and rapidly undergoes a Diels–Alder dimerization. Explain.
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Textbook Question
Draw resonance forms to show the charge distribution on the pyrrole structure.
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Textbook Question
Explain why each compound or ion should be aromatic, antiaromatic, or nonaromatic.
(a)
(b)
(c)
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