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Ch.11 - Reactions of Alcohols
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Not the one you use?Change textbook
Chapter 11, Problem 26c

Propose a mechanism for each reaction.
(c) Chemical reaction diagram showing dehydration of an alcohol to form alkenes, with reactants and products labeled.

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1
Step 1: Recognize the reaction type. This reaction involves dehydration of an alcohol (CH2OH group) under acidic conditions (H2SO4 and heat). The goal is to remove water and form alkenes as products.
Step 2: Protonation of the alcohol group. The sulfuric acid (H2SO4) donates a proton (H+) to the hydroxyl group (-OH) of the alcohol, converting it into a better leaving group (H2O). This step increases the reactivity of the molecule.
Step 3: Formation of a carbocation intermediate. The water molecule leaves, generating a carbocation at the carbon where the alcohol group was attached. This carbocation is the key intermediate in the reaction.
Step 4: Rearrangement and elimination. The carbocation can undergo rearrangement to form more stable carbocations if possible. Then, elimination occurs where a proton is removed from a neighboring carbon atom, leading to the formation of double bonds (alkenes).
Step 5: Formation of multiple products. Depending on the position of the double bond and the stability of the resulting alkenes, multiple products can form. In this case, the products are cyclopentene, methylenecyclopentane, and 1-methylcyclopentene.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Reaction Mechanism

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