Be sure that you've familiarized yourself with the second set of formulas presented in this section by working C5–C8 in the Concept and Vocabulary Check. In Exercises 9–22, express each sum or difference as a product. If possible, find this product's exact value. sin x + sin 2x
Table of contents
- 0. Review of College Algebra4h 45m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
6. Trigonometric Identities and More Equations
Introduction to Trigonometric Identities
Problem 5.RE.34
Textbook Question
Find values of the sine and cosine functions for each angle measure.
B, given cos 2B = 1/8 , 540° < 2B < 720°
Verified step by step guidance1
Identify the given information: \( \cos 2B = \frac{1}{8} \) and the angle range \( 540^\circ < 2B < 720^\circ \). This means \( 2B \) is in the third or fourth quadrant since \( 540^\circ = 360^\circ + 180^\circ \) and \( 720^\circ = 2 \times 360^\circ \).
Determine the quadrant of \( 2B \) based on the given range. Since \( 540^\circ < 2B < 720^\circ \), \( 2B \) lies between \( 180^\circ \) and \( 360^\circ \) after subtracting \( 360^\circ \) (because cosine is periodic with period \( 360^\circ \)). This places \( 2B \) effectively in the third or fourth quadrant of the unit circle.
Use the double-angle identity for cosine: \( \cos 2B = 2 \cos^2 B - 1 \). Substitute \( \cos 2B = \frac{1}{8} \) to get the equation \( \frac{1}{8} = 2 \cos^2 B - 1 \).
Solve for \( \cos B \) by isolating \( \cos^2 B \): \[ 2 \cos^2 B = 1 + \frac{1}{8} = \frac{9}{8} \implies \cos^2 B = \frac{9}{16} \]. Then, \( \cos B = \pm \frac{3}{4} \).
Determine the correct sign of \( \cos B \) by considering the quadrant of \( B \). Since \( 2B \) is between \( 540^\circ \) and \( 720^\circ \), \( B \) is between \( 270^\circ \) and \( 360^\circ \), which is the fourth quadrant where cosine is positive and sine is negative. Use the Pythagorean identity \( \sin^2 B = 1 - \cos^2 B \) to find \( \sin B \), taking the negative root for sine.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Double-Angle Identities
Double-angle identities relate trigonometric functions of an angle to functions of twice that angle. For cosine, cos(2B) can be expressed as 2cos²(B) - 1 or 1 - 2sin²(B). These identities help find sine and cosine values of B when cos(2B) is known.
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Double Angle Identities
Angle Measurement and Quadrants
Understanding the angle's quadrant is essential because sine and cosine signs depend on the quadrant. Since 540° < 2B < 720°, 2B lies in the third or fourth revolution, affecting the possible values and signs of sine and cosine for B.
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Quadratic Formula
Inverse Trigonometric Functions and Solving Equations
To find angle B from cos(2B) = 1/8, inverse cosine is used. Solving for B requires manipulating the equation and considering the periodicity of trigonometric functions to find all valid solutions within the given interval.
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How to Solve Linear Trigonometric Equations
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