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Multiple Choice
Which molecule represents the intermediate step between glycolysis and the citric acid cycle?
A
Citrate
B
Lactate
C
Oxaloacetate
D
Acetyl-CoA
Verified step by step guidance
1
Understand the context: Glycolysis is the metabolic pathway that breaks down glucose into pyruvate, producing ATP and NADH. The citric acid cycle (also known as the Krebs cycle) is the next stage of cellular respiration, where acetyl groups are oxidized to produce more ATP, NADH, and FADH2.
Identify the intermediate step: After glycolysis, pyruvate is converted into acetyl-CoA in a process called pyruvate decarboxylation. This reaction is catalyzed by the pyruvate dehydrogenase complex.
Describe the reaction: Pyruvate is decarboxylated (loses a carbon atom as CO₂), and the remaining two-carbon molecule is attached to coenzyme A, forming acetyl-CoA. This step also produces NADH from NAD⁺.
Explain the role of acetyl-CoA: Acetyl-CoA is the molecule that enters the citric acid cycle, where its acetyl group combines with oxaloacetate to form citrate, initiating the cycle.
Clarify why other options are incorrect: Citrate is a product of the citric acid cycle, lactate is formed during anaerobic glycolysis, and oxaloacetate is a molecule in the citric acid cycle that combines with acetyl-CoA but is not the intermediate step.