Textbook Question
a. Draw the structure of cis-CH3CH=CHCH2CH3 showing the pi bond with its proper geometry.
b. Circle the six coplanar atoms in this compound.
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Ch.1 - Structure and Bonding
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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Table of contents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
Chapter 1, Problem 55f
Draw orbital pictures of the pi bonding in the following compounds:
f. CH3CH=NCH=C=O
Verified step by step guidance1
Identify the pi bonds in the compound CH3CH=NCH=C=O. The pi bonds are present in the C=N, C=C, and C=O bonds.
For each pi bond, determine the hybridization of the atoms involved. Typically, atoms involved in pi bonds are sp2 or sp hybridized, allowing for the formation of pi bonds through the overlap of unhybridized p orbitals.
Draw the molecular structure of the compound, indicating the sigma bonds first. The sigma bonds are formed by the overlap of hybridized orbitals.
For each pi bond, illustrate the side-by-side overlap of the unhybridized p orbitals. This overlap forms the pi bond, which is above and below the plane of the atoms involved in the bond.
Ensure that the pi bonds are correctly represented in the orbital diagram, showing the delocalization of electrons where applicable, especially in conjugated systems like this one.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Pi Bonding
Pi bonds are a type of covalent bond that result from the sideways overlap of p orbitals. Unlike sigma bonds, which are formed by head-on overlap, pi bonds are formed above and below the plane of the atoms involved. They are crucial in double and triple bonds, providing additional bonding strength and influencing molecular geometry.
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Sigma bonds and pi bonds
Orbital Hybridization
Orbital hybridization is the concept of mixing atomic orbitals to form new hybrid orbitals, which can then form sigma and pi bonds. In the context of pi bonding, understanding the hybridization state of each atom (such as sp, sp2, or sp3) helps determine the number and type of bonds an atom can form, as well as the geometry of the molecule.
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04:58Bond sites, hybridization, and intermediate orbitals
Molecular Geometry
Molecular geometry refers to the three-dimensional arrangement of atoms within a molecule. It is determined by the number of bonds and lone pairs around a central atom, influencing the molecule's physical and chemical properties. In compounds with multiple pi bonds, geometry affects how orbitals overlap and the overall stability of the molecule.
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07:44Molecular Geometry Explained.
Related Practice
Textbook Question
Circle the coplanar atoms in the following structure:
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Textbook Question
Predict the hybridization and geometry of the carbon and nitrogen atoms in the following molecules and ions. (Hint: Resonance.)
f.
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Textbook Question
Draw orbital pictures of the pi bonding in the following compounds:
a. CH3COCH3
b. HCN
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Textbook Question
In pent-2-yne (CH3CCCH2CH3), there are four atoms in a straight line. Use dashed lines and wedges to draw a three-dimensional representation of this molecule, and circle the four atoms that are in a straight line.
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Textbook Question
Draw orbital pictures of the pi bonding in the following compounds:
e. CH3CH=C=CHCH3
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