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Ch.6 - Alkyl Halides; Nucleophilic Substitution
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Not the one you use?Change textbook
Chapter 6, Problem 54

Furfuryl chloride can undergo substitution by both SN2 and SN1 mechanisms. Because it is a 1° alkyl halide, we expect SN2 but not SN1 reactions. Draw a mechanism for the SN1 reaction shown below, paying careful attention to the structure of the intermediate. How can this primary halide undergo SN1 reactions?

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Step 1: Analyze the structure of furfuryl chloride. Furfuryl chloride is a primary alkyl halide attached to a furan ring. The furan ring is aromatic and can stabilize a carbocation through resonance.
Step 2: Understand the SN1 mechanism. In an SN1 reaction, the leaving group (Cl in this case) departs first, forming a carbocation intermediate. The stability of the carbocation is crucial for the reaction to proceed.
Step 3: Draw the mechanism for the SN1 reaction. The chloride ion leaves, forming a furfuryl carbocation. The carbocation is stabilized by resonance with the aromatic furan ring, which makes the SN1 pathway feasible despite the primary nature of the alkyl halide.
Step 4: Nucleophilic attack. The sodium formate (NaOCHO) provides the formate ion (HCOO⁻), which acts as the nucleophile. It attacks the carbocation, forming furfuryl formate.
Step 5: Explain why the primary halide undergoes SN1. The resonance stabilization of the furfuryl carbocation by the aromatic furan ring allows the SN1 mechanism to occur, even though primary alkyl halides typically favor SN2 reactions.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

S<sub>N</sub>1 Mechanism

The S<sub>N</sub>1 mechanism is a type of nucleophilic substitution reaction that involves two main steps: the formation of a carbocation intermediate and the subsequent attack by a nucleophile. This mechanism is favored in tertiary and some secondary alkyl halides due to the stability of the carbocation formed. In the case of furfuryl chloride, despite being a primary halide, the presence of the electron-withdrawing oxygen can stabilize the carbocation, allowing for S<sub>N</sub>1 reactivity.
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Carbocation Stability

Carbocation stability is a crucial factor in determining the pathway of nucleophilic substitution reactions. Carbocations are positively charged species that can be stabilized by adjacent electron-donating groups or resonance. In the case of furfuryl chloride, the resonance from the adjacent aromatic ring and the oxygen atom can help stabilize the carbocation intermediate, making S<sub>N</sub>1 reactions feasible even for a primary halide.
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Nucleophilic Substitution Reactions

Nucleophilic substitution reactions involve the replacement of a leaving group (like a halide) by a nucleophile. These reactions can proceed via S<sub>N</sub>1 or S<sub>N</sub>2 mechanisms, depending on the structure of the substrate and the conditions. Understanding the nature of the nucleophile and the leaving group, as well as the sterics and electronics of the substrate, is essential for predicting the outcome of these reactions, as illustrated in the reaction of furfuryl chloride with sodium formate.
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Related Practice
Textbook Question

Triethyloxonium tetrafluoroborate, (CH3CH2)3O+ BF4, is a solid with melting point 91–92°C. Show how this reagent can transfer an ethyl group to a nucleophile (Nuc:) in an SN2 reaction. What is the leaving group? Why might this reagent be preferred to using an ethyl halide? (Consult Table 6-2)

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Textbook Question

Propose mechanisms to account for the observed products in the following reactions.

(b)

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Textbook Question

Using 1,2-dimethylcyclohexene as your starting material, show how you would synthesize the following compounds. (Once you have shown how to synthesize a compound, you may use it as the starting material in any later parts of this problem.) If a chiral product is shown, assume that it is part of a racemic mixture.

(f)

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Textbook Question

The following reaction takes place under second-order conditions (strong nucleophile), yet the structure of the product shows rearrangement. Also, the rate of this reaction is several thousand times faster than the rate of substitution of ­hydroxide ion on 2-chlorobutane under similar conditions. Propose a mechanism to explain the enhanced rate and ­rearrangement observed in this unusual reaction. (“Et” is the abbreviation for ethyl.)

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Textbook Question

Propose mechanisms to account for the observed products in the following reactions.

(a)

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Textbook Question

Because the SN1 reaction goes through a flat carbocation, we might expect an optically active starting material to give a completely racemized product. In most cases, however, SN1 reactions actually give more of the inversion product. In general, as the stability of the carbocation increases, the excess inversion product decreases. Extremely stable carbocations give completely racemic products. Explain these observations.

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