BackA 1.20 cm tall object is 50.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300.0 cm to the right of the first lens along the same optic axis. Find the location and height of the image (call it I1) formed by the lens with a focal length of 40.0 cm.
Repeat Exercise 34.41 using the same lenses except for the following changes: The second lens is a diverging lens having a focal length of magnitude 60.0 cm.
Two converging lenses, one with ƒ = 4.0 cm and the other with ƒ = 41 cm , are made into a telescope. (a) Determine the telescope’s length and its magnification. Which lens should be the eyepiece? (b) Assume these lenses are now combined to make a microscope; if the magnification needs to be 125 x , how long would the microscope be? Explain why the result in (b) is so impractical.
A small object is 25.0 cm from a diverging lens as shown in Fig. 33–48. A converging lens with a focal length of 12.0 cm is 30.0 cm to the right of the diverging lens. The two-lens system forms a real inverted image 17.0 cm to the right of the converging lens. What is the focal length of the diverging lens?
(II) Two lenses, one converging with focal length 20.0 cm and one diverging with focal length -10.0 cm, are placed 25.0 cm apart. An object is placed 60.0 cm in front of the converging lens. Determine (a) the position and (b) the magnification of the final image formed. (c) Sketch a ray diagram for this system.