Textbook Question
For each pair, choose the haloalkane that would react most quickly in an SN1 or E1 reaction.
(a)
1296
views
Ch. 12 - Substitution and Elimination: Reactions of Haloalkanes
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471
Not the one you use?Change textbookSelect a different textbook
Table of contents
- Ch. 2 - General Chemistry Translated: Finding the Electrons114
- Ch. 3 - Alkanes and Cycloalkanes: Properties and Conformational Analysis109
- Ch. 4 - Acids and Bases: Electron Flow144
- Ch. 5 - Chemical Reaction Analysis: Thermodynamics and Kinetics118
- Ch. 6 - Stereoisomerism: Arrangement of Atoms in Space112
- Ch. 7 - Principles of Green (Organic) Chemistry3
- Ch. 8 - Alkenes I: Properties and Electrophilic Additions158
- Ch. 9 - Alkenes II: Oxidation and Reduction150
- Ch. 10 - Alkynes: Electrophilic Addition and Redox Reactions101
- Ch. 11 - Properties and Synthesis of Alkyl Halides: Radical Reactions108
- Ch. 12 - Substitution and Elimination: Reactions of Haloalkanes172
- Ch. 13 - Alcohols, Ethers and Related Compounds: Substitution and Elimination239
- Ch. 14 - Structural Identification I: Infrared Spectroscopy and Mass Spectrometry54
- Ch. 15 - Structural Identification II: Nuclear Magnetic Resonance Spectroscopy93
- Ch. 16 - Metals in Organic Chemistry48
- Ch. 17 - Carbonyl Addition Reactions: Aldehydes and Ketones45
- Ch. 18 - Nucleophilic Acyl Substitution I: Carboxylic Acids18
- Ch. 19 - Nucleophilic Acyl Substitution II: Carboxylic Acid Derivatives39
- Ch. 20 - Enolates: Carbonyl Addition and Substitution13
- Ch. 21 - Conjugated Systems I: Stability and Addition Reactions56
- Ch. 22 - Conjugated Systems II: Pericyclic Reactions54
- Ch. 23 - Benzene I: Aromatic Stability and Substitution Reactions64
- Ch. 24 - Benzene II: Reactions Influenced by the Aromatic Ring62
- Ch. 25 - Amines: Structure, Reactions, and Synthesis27
- Ch. 26 - Amino Acids, Proteins, and Peptide Synthesis9
- Ch. 27 - Carbohydrates, Nucleic Acids, and Lipids54
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471Not the one you use?Change textbook
All textbooks
Mullins 1st EditionCh. 12 - Substitution and Elimination: Reactions of HaloalkanesProblem 60a
Mullins 1st EditionCh. 12 - Substitution and Elimination: Reactions of HaloalkanesProblem 60aChapter 11, Problem 60a
Suggest a bromoalkane and the conditions necessary to produce the alkenes shown.
(a) 
Verified step by step guidance1
Step 1: Identify the alkenes shown in the problem. Determine their structure, including the position of the double bond and the number of carbons in the chain. This will help you deduce the possible precursor bromoalkane.
Step 2: Recall that alkenes can be formed via elimination reactions (E2 or E1 mechanisms). In these reactions, a hydrogen atom and a leaving group (such as bromine) are removed from adjacent carbons to form a double bond.
Step 3: Suggest a bromoalkane that could serve as the precursor. The bromoalkane should have the bromine atom attached to a carbon adjacent to the carbon that will form the double bond in the alkene. For example, if the alkene has a double bond between C2 and C3, the bromoalkane could be 2-bromopropane.
Step 4: Specify the conditions necessary for the elimination reaction. For an E2 mechanism, use a strong base such as NaOH or KOH in an aprotic solvent like ethanol. For an E1 mechanism, use a weaker base and heat to promote carbocation formation.
Step 5: Consider regioselectivity and stereoselectivity. If multiple alkenes are possible, the major product will typically follow Zaitsev's rule, where the more substituted alkene is favored. Ensure the conditions align with the desired product.
Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
5mWas this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Bromoalkanes
Bromoalkanes are organic compounds that contain a bromine atom attached to an alkane chain. They are important intermediates in organic synthesis and can undergo various reactions, such as elimination or substitution, to form alkenes. Understanding the structure and reactivity of bromoalkanes is crucial for predicting the products of chemical reactions.
Elimination Reactions
Elimination reactions involve the removal of atoms or groups from a molecule, resulting in the formation of a double bond. In the case of bromoalkanes, conditions such as strong bases (e.g., KOH or NaOH) and heat can promote elimination, leading to the formation of alkenes. The mechanism often follows either an E1 or E2 pathway, depending on the substrate and conditions.
Recommended video:
Guided course
00:40
Recognizing Elimination Reactions.
Reaction Conditions
The conditions under which a reaction occurs significantly influence the products formed. For the conversion of bromoalkanes to alkenes, factors such as temperature, solvent, and the presence of a strong base are critical. High temperatures and the use of polar aprotic solvents can favor elimination over substitution, thus promoting alkene formation.
Recommended video:
1:18EAS Reactions of Pyridine Example 1
Related Practice
Textbook Question
In Chapter 10, you learned how to make an alkyne by acetylide alkylation with a 1° haloalkane. Suggest a mechanism by which this reaction occurs.
1095
views
Textbook Question
Acetylide alkylation, from Assessment 12.61, fails to give the desired product with 2° haloalkanes. Why? What is the actual product of this reaction?
1011
views
Textbook Question
For each pair, choose the haloalkane that would react most quickly in an SN1 or E1 reaction.
(b)
515
views
Textbook Question
Suggest a bromoalkane and the conditions necessary to produce the alkenes shown.
(b)
1249
views
Textbook Question
For each pair, choose the haloalkane that would react most quickly in an Sₙ1 or E1 reaction.
(c)
1491
views