Textbook Question
Predict the product of the following Lewis acid–Lewis base reactions.
(c)
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Ch. 4 - Acids and Bases: Electron Flow
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471
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Table of contents
- Ch. 2 - General Chemistry Translated: Finding the Electrons114
- Ch. 3 - Alkanes and Cycloalkanes: Properties and Conformational Analysis109
- Ch. 4 - Acids and Bases: Electron Flow144
- Ch. 5 - Chemical Reaction Analysis: Thermodynamics and Kinetics118
- Ch. 6 - Stereoisomerism: Arrangement of Atoms in Space112
- Ch. 7 - Principles of Green (Organic) Chemistry3
- Ch. 8 - Alkenes I: Properties and Electrophilic Additions158
- Ch. 9 - Alkenes II: Oxidation and Reduction150
- Ch. 10 - Alkynes: Electrophilic Addition and Redox Reactions101
- Ch. 11 - Properties and Synthesis of Alkyl Halides: Radical Reactions108
- Ch. 12 - Substitution and Elimination: Reactions of Haloalkanes172
- Ch. 13 - Alcohols, Ethers and Related Compounds: Substitution and Elimination239
- Ch. 14 - Structural Identification I: Infrared Spectroscopy and Mass Spectrometry54
- Ch. 15 - Structural Identification II: Nuclear Magnetic Resonance Spectroscopy93
- Ch. 16 - Metals in Organic Chemistry48
- Ch. 17 - Carbonyl Addition Reactions: Aldehydes and Ketones45
- Ch. 18 - Nucleophilic Acyl Substitution I: Carboxylic Acids18
- Ch. 19 - Nucleophilic Acyl Substitution II: Carboxylic Acid Derivatives39
- Ch. 20 - Enolates: Carbonyl Addition and Substitution13
- Ch. 21 - Conjugated Systems I: Stability and Addition Reactions56
- Ch. 22 - Conjugated Systems II: Pericyclic Reactions54
- Ch. 23 - Benzene I: Aromatic Stability and Substitution Reactions64
- Ch. 24 - Benzene II: Reactions Influenced by the Aromatic Ring62
- Ch. 25 - Amines: Structure, Reactions, and Synthesis27
- Ch. 26 - Amino Acids, Proteins, and Peptide Synthesis9
- Ch. 27 - Carbohydrates, Nucleic Acids, and Lipids54
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471Not the one you use?Change textbook
Chapter 3, Problem 73c
Suggest an arrow-pushing mechanism for each of the following acid–base reactions
(c) 
Verified step by step guidance1
Identify the acid and base in the reaction. The acid is the species donating a proton (H⁺), and the base is the species accepting the proton.
Draw the Lewis structures of the acid and base to visualize the electron pairs involved in the reaction. Highlight the lone pair on the base that will interact with the proton from the acid.
Use curved arrows to represent the movement of electrons. Start the arrow at the lone pair of the base and point it toward the hydrogen atom of the acid, indicating the formation of a bond between the base and the proton.
Show the breaking of the bond between the hydrogen atom and the atom it was originally attached to in the acid. Use a curved arrow starting at the bond and pointing toward the atom that will retain the electrons after the bond breaks.
Verify the products of the reaction. The base becomes protonated, forming its conjugate acid, and the acid loses a proton, forming its conjugate base. Ensure that charges and electron counts are balanced in the final structures.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Acid-Base Theory
Acid-base theory explains the behavior of acids and bases in chemical reactions. According to the Brønsted-Lowry theory, acids are proton donors while bases are proton acceptors. Understanding this concept is crucial for predicting the direction of acid-base reactions and the formation of conjugate acids and bases.
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02:49
The Lewis definition of acids and bases.
Arrow-Pushing Mechanism
Arrow-pushing mechanisms are a way to illustrate the movement of electrons during chemical reactions. In these diagrams, arrows represent the flow of electron pairs, indicating how bonds are formed or broken. This visual representation helps in understanding the stepwise progression of reactions, particularly in acid-base interactions.
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04:32General Mechanism
Conjugate Acid-Base Pairs
Conjugate acid-base pairs are related species that differ by the presence of a proton. When an acid donates a proton, it forms its conjugate base, while the base that accepts the proton becomes its conjugate acid. Recognizing these pairs is essential for analyzing the equilibrium of acid-base reactions and predicting the products formed.
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Related Practice
Textbook Question
Using pKa values for the conjugate acids of the bases on each side of the reaction arrow, identify which side of the equilibrium would be favored in the following hypothetical reactions.
(c)
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Textbook Question
Suggest an arrow-pushing mechanism for each of the following acid–base reactions.
(d) [an intramolecular reaction]
1090
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Textbook Question
Predict the product of the following Lewis acid–Lewis base reactions.
(d) [an intramolecular reaction]
1448
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Textbook Question
One of the more reactive species we will study in organic chemistry is the carbene (molecular formula of CH2). The carbene can react as both a Lewis acid and a Lewis base. Explain these properties.
1103
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Textbook Question
BCl3 has an empty p orbital, so it is a strong Lewis acid. Would you expect an amide to react with BCl3 at nitrogen or oxygen?
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