Textbook Question
For the following equilibrium processes and the corresponding ∆G°, indicate whether you expect the equilibrium constant to be greater than, equal to, or less than 1. Justify your expectation in words.
(a)
1159
views
Ch. 5 - Chemical Reaction Analysis: Thermodynamics and Kinetics
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471
Not the one you use?Change textbookSelect a different textbook
Table of contents
- Ch. 2 - General Chemistry Translated: Finding the Electrons114
- Ch. 3 - Alkanes and Cycloalkanes: Properties and Conformational Analysis109
- Ch. 4 - Acids and Bases: Electron Flow144
- Ch. 5 - Chemical Reaction Analysis: Thermodynamics and Kinetics118
- Ch. 6 - Stereoisomerism: Arrangement of Atoms in Space112
- Ch. 7 - Principles of Green (Organic) Chemistry3
- Ch. 8 - Alkenes I: Properties and Electrophilic Additions158
- Ch. 9 - Alkenes II: Oxidation and Reduction150
- Ch. 10 - Alkynes: Electrophilic Addition and Redox Reactions101
- Ch. 11 - Properties and Synthesis of Alkyl Halides: Radical Reactions108
- Ch. 12 - Substitution and Elimination: Reactions of Haloalkanes172
- Ch. 13 - Alcohols, Ethers and Related Compounds: Substitution and Elimination239
- Ch. 14 - Structural Identification I: Infrared Spectroscopy and Mass Spectrometry54
- Ch. 15 - Structural Identification II: Nuclear Magnetic Resonance Spectroscopy93
- Ch. 16 - Metals in Organic Chemistry48
- Ch. 17 - Carbonyl Addition Reactions: Aldehydes and Ketones45
- Ch. 18 - Nucleophilic Acyl Substitution I: Carboxylic Acids18
- Ch. 19 - Nucleophilic Acyl Substitution II: Carboxylic Acid Derivatives39
- Ch. 20 - Enolates: Carbonyl Addition and Substitution13
- Ch. 21 - Conjugated Systems I: Stability and Addition Reactions56
- Ch. 22 - Conjugated Systems II: Pericyclic Reactions54
- Ch. 23 - Benzene I: Aromatic Stability and Substitution Reactions64
- Ch. 24 - Benzene II: Reactions Influenced by the Aromatic Ring62
- Ch. 25 - Amines: Structure, Reactions, and Synthesis27
- Ch. 26 - Amino Acids, Proteins, and Peptide Synthesis9
- Ch. 27 - Carbohydrates, Nucleic Acids, and Lipids54
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471Not the one you use?Change textbook
All textbooks
Mullins 1st EditionCh. 5 - Chemical Reaction Analysis: Thermodynamics and KineticsProblem 6b
Mullins 1st EditionCh. 5 - Chemical Reaction Analysis: Thermodynamics and KineticsProblem 6bChapter 4, Problem 6b
Provide a reasonable arrow-pushing mechanism for the following Lewis acid–Lewis base reactions.
(b) 
Verified step by step guidance1
Identify the Lewis acid and Lewis base in the reaction. A Lewis acid is an electron pair acceptor, while a Lewis base is an electron pair donor. Look for species with empty orbitals (Lewis acid) and lone pairs of electrons (Lewis base).
Determine the site of interaction between the Lewis acid and Lewis base. Typically, the lone pair on the Lewis base will attack the electron-deficient center of the Lewis acid.
Draw the curved arrow to represent the movement of electrons. The arrow should start from the lone pair on the Lewis base and point toward the electron-deficient atom of the Lewis acid.
Update the structure of the product formed after the electron pair donation. The Lewis base will form a bond with the Lewis acid, and the electron density will shift accordingly.
Verify the final product to ensure that all atoms obey the octet rule (if applicable) and that charges are properly assigned based on the electron movement.
Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
3mWas this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Lewis Acids and Bases
Lewis acids are electron pair acceptors, while Lewis bases are electron pair donors. This concept expands the definition of acids and bases beyond protons, allowing for a broader range of chemical reactions. Understanding the nature of these species is crucial for predicting reaction outcomes in organic chemistry.
Recommended video:
Guided course
02:49
The Lewis definition of acids and bases.
Arrow-Pushing Mechanism
Arrow-pushing mechanisms are a way to illustrate the movement of electrons during chemical reactions. Curved arrows represent the flow of electron pairs, indicating how bonds are formed or broken. This visual representation helps in understanding the stepwise progression of reactions, particularly in Lewis acid-base interactions.
Recommended video:
Guided course
04:32General Mechanism
Reaction Intermediates
In many Lewis acid-base reactions, intermediates are formed as transient species that exist during the reaction process. Recognizing these intermediates is essential for understanding the overall mechanism and predicting the final products. They often play a critical role in determining the reaction pathway and kinetics.
Recommended video:
Guided course
04:31Stability of Conjugated Intermediates
Related Practice
Textbook Question
Chapter 5 taught us that chemical reactions are random collisions. Experimentally, how can we make molecules collide more often?
1304
views
Textbook Question
Provide a reasonable arrow-pushing mechanism for the following Lewis acid–Lewis base reactions.
(a)
1122
views
Textbook Question
Which is the most acidic compound in each pair?
(c)
1038
views
Textbook Question
For the following equilibrium processes and the corresponding ∆G° , indicate whether you expect the equilibrium constant to be greater than, equal to, or less than 1. Justify your expectation in words.
(b)
807
views
Textbook Question
Which is the most acidic compound in each pair?
(b) HF vs. HCl
1489
views